java.lang.Long cannot be cast to java.lang.Integer - 代码天地

java.lang.Long cannot be cast to java.lang.Integer

其他 2018-07-05 20:07:24 阅读次数: 0

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转载自blog.csdn.net/weixin_41315469/article/details/79865197

java.lang.Long cannot be cast to java.lang.Integer

java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long

java.lang.ClassCastException: java.lang.Long cannot be cast to java.lang.Integer

报错：java.lang.Integer cannot be cast to java.lang.Long

解决java.lang.Long cannot be cast to java.lang.Integer问题

java.lang.Integer cannot be cast to java.lang.Long解决办法

bug：java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long 解决方法

Cause: java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long错误的详细解决方法

已解决java.lang.ClassCastException: class java.lang.Integer cannot be cast to class java.lang.Long

完美解决java.lang.ClassCastException: class java.lang.Integer cannot be cast to class java.lang.Long

## 已解决：`java.lang.ClassCastException: class java.lang.Integer cannot be cast to class java.lang.Long

获取JSONArray 对象中的Long型数据时报错：java.lang.Integer cannot be cast to java.lang.Long

controller层接收一个list，遇到java.lang.Integer cannot be cast to java.lang.Long的错

java.lang.Long cannot be cast to java.lang.String

java.lang.Integer cannot be cast to java.lang.String

java.math.BigDecimal cannot be cast to java.lang.Long

Jedis [B cannot be cast to java.lang.Long 并发异常

java.math.BigDecimal cannot be cast to java.lang.Integer

java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.String

【连接异常】 java.lang.ClassCastException: java.math.BigInteger cannot be cast to java.lang.Long

java.lang.ClassCastException: java.math.BigInteger cannot be cast to java.lang.Long

jedis 出现java.lang.ClassCastException: java.util.ArrayList cannot be cast to java.lang.Long

Redis操作异常: java.lang.ClassCastException: java.lang.Long cannot be cast to [B

java.lang.String cannot be cast to java.lang.Long at android.app.SharedPreferencesImpl.getLong(Share

java 解决 java.lang.Integer cannot be cast to java.lang.String

【java异常】java.lang.Integer cannot be cast to java.lang.String

Hive udtf 报错 java.lang.String cannot be cast to java.lang.Integer

分页结果做缓存报java.lang.Integer cannot be cast to java.lang.String错误

java.lang.String cannot be cast to java.lang.Integer解决办法

成功解决：java.lang.String cannot be cast to java.lang.Integer

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