1001 A+B Format (20)(20 分)
Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input
-1000000 9
Sample Output
-999,991
题目大意:求两个数的和,并用三位分节法表示结果
我的代码如下:
#include <iostream>
#include <string>
using namespace std;
int main()
{
int a,b,sum,i=1,temp;
int s[100000];
cin>>a>>b;
sum=a+b;
if(sum==0)
{//如果合为0,直接输出0
cout<<'0';
system("pause");
return 0;
}
temp=sum;
while(sum!=0)
{//从个位开始逐位存入
s[i]=sum%10;
sum=sum/10;
i++;
}
//输出
if(temp<0)
{
cout<<'-';
}
for(int j=i-1;j>=1;j--)
{
if(j%3==0&&j!=i-1)
{
cout<<',';
}
cout<<abs(s[j]);
}
system("pause");
return 0;
}