HPUACM Freshman Exercises Round 1 [标程]

A

#include <stdio.h>

int main()
{
    int a, b, k;
    while(scanf("%d%d%d", &a, &b, &k) != EOF) {
        printf("%.8lf\n", (double)a / (a + b));
    }
    return 0;
}

B

#include <cstdio>

int main() {
    int n;
    while(scanf("%d", &n) != EOF) {
        if(n % 4 == 0) puts("YES");
        else puts("NO");
    }
    return 0;
}

C

#include <cstdio>
#include <cmath>
typedef long long LL;

const int MAXN = 100000 + 10;
LL dp[MAXN];

void init() {
    for(int i = 1; i <= 100000 + 5; i++) {
        LL ans = 0;
        for(int j = 1; j <= sqrt(i); j++) {
            if(i % j == 0) {
                ans = ans + i / j + j;
                if(j * j == i) ans -= j;
            } 
        }
        dp[i] += ans + dp[i - 1];
    }
} 

int main() {
    int T, L, R;
    init();
    scanf("%d", &T);
    while(T--) {
        scanf("%d %d", &L, &R);
        printf("%lld\n", dp[R] - dp[L - 1]);
    }
    return 0;
}

D

#include<stdio.h>

typedef long long LL;

LL gcd(LL a, LL b) {
    return b ? gcd(b, a % b) : a;
}
int main()
{
    LL n, k, res[10];
    res[0] = 1;
    for(int i = 1; i < 10; ++i) res[i] = res[i - 1] * 10;
    while(scanf("%lld %lld", &n, &k) != EOF) {
        printf("%lld\n", n * res[k] / gcd(n, res[k]));
    }
    return 0;
}

E

#include <cstdio>

int main() {
    int n;
    while(scanf("%d", &n) != EOF) {
        printf("%d\n", n);
    }
    return 0;
}

F

#include<stdio.h>

using namespace std;
#define LL long long

const int MAXN = 1e6+11;
const int inf  = 0x3f3f3f3f;

int prm[MAXN+2],sz=0; bool su[MAXN+2];
void init(){
    su[0]=su[1]=true;
    for(int i=2;i<=MAXN;i++){
        if(!su[i])  prm[++sz]=i;
        for(int j=1;j<=sz;j++){
            LL t=1LL*i*prm[j];
            if(t>=MAXN) break;
            su[t]=true;
            if(i%prm[j]==0) break;
        }
    }
}

int ans[MAXN];
void solve(int m){
    if(m==0||m==1) {
        puts("HAHA");
        return ;
    }
    int id=0;
    for(int i=1;i<=sz&&(LL)prm[i]*prm[i]<=m;i++){
        if(m%prm[i]==0) {
            ans[id++]=prm[i];
            while(m%prm[i]==0)  m/=prm[i];
        }
    }
    if(m>1) ans[id++]=m;

    if(id==0) puts("HAHA");
    else {
        printf("%d\n",id);
        for(int i=0;i<id;i++)
            printf("%d%s",ans[i],i==id-1?"":" ");
        puts("");
    }
}

int main(){
    init();
    int T;scanf("%d",&T);
    while(T--){
        int  m;
        scanf("%d",&m);
        solve(m);
    }
    return 0;
}

or

#include<bits/stdc++.h>
#define LL long long
using namespace std;
const int MAXN = 1e5;
int p[MAXN+2];
int id;
void getn(int n){
    id=0;
    for(int i=2;i*i<=n;i++){
        if(n%i==0) {
           p[id++]=i;
           while(n%i==0){
            n/=i;
           }
        }
    }
    if(n>1) p[id++]=n;
}

int main(){
    int t;cin>>t;
    while(t--){
        int  m; cin>>m;
        getn(m);
        if(m==0||m==1||id==0) puts("HAHA");
        else {
            printf("%d\n",id);
            for(int i=0;i<id;i++)
                printf("%d%s",p[i],i==id-1?"":" ");
            puts("");
        }
    }
    return 0;
}

G

#include <stdio.h>

const int MAXN = (int)1e6 + 5;
int p[MAXN], cnt[MAXN];

void init() {
    for(int i = 2; i * i < MAXN; ++i) {
        if(!p[i]) {
            for(int j = i * i; j < MAXN; j += i) {
                p[j] = 1;
            }
        }
    }
    for(int i = 2; i < MAXN; ++i) {
        if(!p[i]) {
            for(long long j = i; j < MAXN; j *= i) {
                cnt[j] = 1;
            }
        }
    }
    for(int i = 1; i < MAXN; ++i) {
        cnt[i] += cnt[i - 1];
    }
}

int main()
{
    init();
    int n;
    while(scanf("%d", &n) != EOF) {
        printf("%d\n", cnt[n]);
    }
    return 0;
}

H

#include <cstdio>
struct node{
    int hp,sd,sk,tm;
    char nature[2];
}a,b;
int main(){
    int t;
    scanf("%d",&t);
    while (t--){
        a.tm = b.tm = 0;
        scanf("%d%d%d%s%d%d%d%s",&a.hp,&a.sd,&a.sk,a.nature,&b.hp,&b.sd,&b.sk,b.nature);
        if (a.nature[0]!=b.nature[0]){
            if (a.nature[0] == 'W'&&b.nature[0] == 'F'){a.sk*=2;b.sk/=2;}
            else if (a.nature[0] == 'W'&&b.nature[0] == 'G'){a.sk/=2;b.sk*=2;}
            else if (a.nature[0] == 'F'&&b.nature[0] == 'G'){a.sk*=2;b.sk/=2;}
            else if (a.nature[0] == 'F'&&b.nature[0] == 'W'){a.sk/=2;b.sk*=2;}
            else if (a.nature[0] == 'G'&&b.nature[0] == 'W'){a.sk*=2;b.sk/=2;}
            else if (a.nature[0] == 'G'&&b.nature[0] == 'F'){a.sk/=2;b.sk*=2;}
        }
        a.tm = b.hp/a.sk;if (b.hp%a.sk) a.tm+=1;
        b.tm = a.hp/b.sk;if (a.hp%b.sk) b.tm+=1;
        if (a.tm == b.tm) if (a.sd > b.sd) a.tm-=1;else b.tm-=1;
        if (a.tm<b.tm){
            puts("Garry win HAHA! ");
        }else puts("No !!!!");
    }
    return 0;
}

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转载自blog.csdn.net/ctsas/article/details/78515374
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