Serilog记录MongoDB日志报错：requires the binary sub type to be UuidLegacy, not UuidStandard - 代码天地

Serilog记录MongoDB日志报错：requires the binary sub type to be UuidLegacy, not UuidStandard

其他 2018-07-28 18:27:02 阅读次数: 0

NoSuchKey

猜你喜欢

转载自www.cnblogs.com/AlienXu/p/9382857.html

Serilog记录MongoDB日志报错：requires the binary sub type to be UuidLegacy, not UuidStandard

MongoDB 错误be UuidLegacy, not UuidStandard

The GuidRepresentation for the reader is CSharpLegacy, which requires the binary sub type to be Uuid

[Typescript] Using 'Pick' to create a sub-type from original type

[sub]

[ERROR] IDA 加载dump binary 报错 & 反编译报错wrong basic type sizes in compiler settings

三、mysql 报错 Unknown type '14 in column 3 of 5 in binary-encoded result set

【虚拟机报错】错误：不支持的配置：IDE controllers are unsupported for this QEMU binary or machine type

vuex报错TypeError: sub is not a function

vbs报错“Sub不能用括号”

MySQL计算日期的函数DATE_SUB(d,INTERVAL expr type)

错误“checking build system type... config.sub: missing argument”的解决办法

[Swift]有用的Binary Heap Type类

Data type conversion in MongoDB

Cydia sub-process /usr/libexec/cydia/cydo 报错 100

EPICS简单实例2 -- subroutine记录(sub)介绍与使用

hibernate type=MyISAM 报错

rabbitmq报错type

Content-Type记录

sub main()

sub esp

正则的sub

Sub过程

Unknown type '246 in column 0 of 1 in binary-encoded result set的解决办法

iOS动态库之An empty identity is not valid when signing a binary for the product type 'Dynamic Library'

Query and Extract Refining Event Extraction as Type-oriented Binary Decoding 论文解读

Flutter报错: type ‘double‘ is not a subtype of type ‘int?‘或type ‘int‘ is not a subtype of type ‘double

解决Hadoop报错：Failed to locate the winutils binary in the hadoop binary path

Failed to locate the winutils binary in the hadoop binary path 报错解决

type()

今日推荐

周排行

简述ArrayList、Vector、LinkedList三者的特点

什么是 Shell？

湖南省株洲市谷歌高清卫星地图下载

99乘法表（for循环嵌套）

pat-1027

简单算法面试题（附自己的答案）

全国乡镇边界 / 乡镇界线 / 乡镇行政面数据分享

【JAVA】学习记录【递归查询子节点】

CSS里的BFC和IFC的用法

04.CSS3 transition属性及案例分享

每日归档

更多

2025-02-10(0)

2025-02-09(0)

2025-02-08(0)

2025-02-07(0)

2025-02-06(0)

2025-02-05(0)

2025-02-04(0)

2025-02-03(0)

2025-02-02(0)

2025-02-01(0)