UVa 1368 DNA Consensus String

这道字符串也处理了很多麻烦的情况啊啊啊啊啊,感觉字符串的问题都很注重细节(其实这是一道简单模拟吧。。。),可能是找错了方法,这道题又做了四十分钟左右。。。好难受明明是一道水题结果一直在Debuuuuuug。。先想好思路再下手,效果一定会好很多。。这紫书给的题真的要吐槽一下子,说是难题吧思路简单,说是水题呢半天敲不出来,自己功底太弱,加油码!
#include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
#include<vector>
#include<set>
#include<map>
#include<queue>
#include<cmath>
#include<time.h>
using namespace std;
#define inf 0x3f3f3f3f
char a[52][1005];
int main()
{
    int n, m;
    int t;
    scanf("%d",&t);
    int num[4];
    while(t --)
    {
        scanf("%d%d",&n,&m);
        for(int i = 0; i < n; i ++)
            scanf("%s",a[i]);
        char ans[1005];
        char ans1;
        int ans2 = 0;
        int maxy = -1;
        for(int i = 0; i < m; i ++)
        {
            memset(num, 0, sizeof(num));
            maxy = -1;
            for(int j = 0; j < n; j ++)
            {
                if(a[j][i] == 'A')
                {
                    num[0] ++;
                    if(num[0] >= maxy)
                    {
                        maxy = num[0];
                        ans1 = 'A';
                    }
                }
                if(a[j][i] == 'C')
                {
                    num[1] ++;
                    if(num[1] == num[0]){}
                    else if(num[1] >= maxy)
                    {
                        maxy = num[1];
                        ans1 = 'C';
                    }
                }
                if(a[j][i] == 'G')
                {
                    num[2] ++;
                    if((num[2] == num[1]) || (num[2] == num[0])){}
                    else if(num[2] >= maxy)
                    {
                        maxy = num[2];
                        ans1 = 'G';
                    }
                }
                if(a[j][i] == 'T')
                {
                    num[3] ++;
                    if((num[3] == num[2]) || (num[3] == num[0]) || (num[3] == num[1])){}
                    else if(num[3] >= maxy)
                    {
                        maxy = num[3];
                        ans1 = 'T';
                    }
                }
            }
            ans2 += (n - maxy);
            ans[i] = ans1;
        }
        for(int i = 0; i < m; i ++)
            cout<<ans[i];
        cout<<endl;
        printf("%d\n",ans2);
    }
    return 0;
}

猜你喜欢

转载自blog.csdn.net/qq_41444888/article/details/80523889