LOJ-#6281. 数列分块入门 5

题目链接:https://ajax.loj.ac/problem/6281

#include<bits/stdc++.h>
#define ll long long
using namespace std;
const int maxn = 5e4 + 5;
int blo, opt, l, r, c, a[maxn], flag[maxn], pos[maxn], n, sum[maxn];
void sovle_sqrt(int x)
{
    if(flag[x]) return;
    flag[x] = 1;
    sum[x] = 0;
    for (int i = (x-1)*blo+1; i <= x*blo; i++){
        a[i] = sqrt(a[i]);
        sum[x] += a[i];
        if(a[i]>1) flag[x] = 0;
    }
}
int add(int l, int r)
{
    for (int i = l; i <= min(r, pos[l]*blo); i++){
        sum[pos[l]]-= a[i];
        a[i] = sqrt(a[i]);
        sum[pos[l]] += a[i];
    }
    if(pos[l] != pos[r]){
        for (int i = (pos[r]-1)*blo+1; i <= r; i++){
            sum[pos[r]] -= a[i];
            a[i] = sqrt(a[i]);
            sum[pos[r]] += a[i];
        }
    }
    for (int i = pos[l]+1; i <= pos[r]-1; i++){
        sovle_sqrt(i);
    }
}
int query(int l, int r)
{
    int ans = 0;
    for (int i = l;i <= min(pos[l]*blo, r); i++){
        ans += a[i];
    }
    if(pos[l] != pos[r]){
        for (int i = (pos[r]-1)*blo+1; i<= r; i++){
            ans += a[i];
        }
    }
    for (int i = pos[l]+1; i <= pos[r]-1; i++)
        ans += sum[i];
    return ans;
}
int main()
{
    scanf("%d", &n);
    blo = sqrt(n);
    for (int i = 1; i <= n; i++) scanf("%d", &a[i]),pos[i] = (i-1)/blo +1, sum[pos[i]] += a[i];

    for(int i = 1; i <= n; i++){
        scanf("%d%d%d%d", &opt, &l, &r, &c);
        if(opt == 0) add(l, r);
        else printf("%d\n",query(l, r));
    }
}

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转载自blog.csdn.net/qq_37602930/article/details/81213784