原题链接:
https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1756
这道题用STL解答还是比较简单的,下面就给大家分享用 set 和 map 的 AC 。
解法一(map):
#include <iostream>
#include <string>
#include <map>
using namespace std;
map<string, char> mmp;
int main(void)
{
int i, idex = 0;
char ch, str[200];
while (ch = getchar()) {
if (ch == EOF) break;
if (isupper(ch)) ch = tolower(ch);
if (islower(ch)) str[idex++] = ch;
else {
str[idex++] = '\0';
if (idex > 1) mmp[str] = 1;
idex = 0;
}
}
for (map<string, char>::iterator i = mmp.begin(); i != mmp.end(); i++)
puts(i -> first.c_str());
return 0;
}
解法二(set):
#include <iostream>
#include <sstream>
#include <string>
#include <set>
using namespace std;
set<string> se;
string x, y;
int main(void)
{
while (cin >> x) {
for (int i = 0; i < x.length(); i++) {
if (isalpha(x[i]))
x[i] = tolower(x[i]);
else x[i] = ' ';
}
stringstream ss(x);//文件流
while (ss >> y) se.insert(y);
}
for (set<string>::iterator it = se.begin(); it != se.end(); it++)
cout << *it << '\n';
return 0;
}