iOS 遍历数组，提取相同元素存入另外一个数组

代码如下：

NSArray *array1 = @[@"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-01",@"2016-10-02",@"2016-10-03",

                        @"2016-10-04",@"2016-10-06",@"2016-10-08",

                        @"2016-10-05",@"2016-10-07",@"2016-10-09"];
    NSMutableArray *array = [NSMutableArray arrayWithArray:array1];

    NSMutableArray *dateMutablearray = [@[] mutableCopy];
    for (int i = 0; i < array.count; i ++) {

        NSString *string = array[i];

        NSMutableArray *tempArray = [@[] mutableCopy];

        [tempArray addObject:string];

        for (int j = i+1; j < array.count; j ++) {

            NSString *jstring = array[j];

            if([string isEqualToString:jstring]){

                [tempArray addObject:jstring];

                [array removeObjectAtIndex:j];
                j -= 1;

            }

        }

        [dateMutablearray addObject:tempArray];

    }

    NSLog(@"dateMutable:%@",dateMutablearray);

输出结果是：

作者：SuperDi
链接：http://www.jianshu.com/p/cce9c564f05a
來源：简书
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