D - Single-use Stones -(思维-frog过河)

D - Single-use Stones

 CodeForces - 965D 

在L段上求最小值

更新最小值

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
ll n,l;
ll a[100005];
ll sum[100005];
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    memset(sum,0,sizeof(sum));
    ll ans=LONG_MAX;
    cin>>n>>l;
    for(int i=1; i<n; i++)
    {
        cin>>a[i];
        sum[i]=sum[i-1]+a[i];
    }
    for(int i=l; i<n; i++)
        ans=min(ans,sum[i]-sum[i-l]);
    cout<<ans<<endl;
}

猜你喜欢

转载自blog.csdn.net/BePosit/article/details/81559550