【每日一题】Squares UVA - 201 暴力+输出坑

题意 给你n*n的图，让你数正方形

题解：暴力for每个点，对于每个点从它出发顺时针走一个正方形。走完就ans[i]++;

坑：多输了一行******，然后在那里手摸样例，无限debug orz

#define _CRT_SECURE_NO_WARNINGS
#include<cmath>
#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<cstring>
#include<ctime>
using namespace std;
#define rep(i,t,n)  for(int i =(t);i<=(n);++i)
#define per(i,n,t)  for(int i =(n);i>=(t);--i)
#define mmm(a,b) memset(a,b,sizeof(a))
typedef long long ll;
const int maxn = 2e6 + 10;
const ll mod = 1e9 + 7;
void smain();
#define ONLINE_JUDGE
int main() {
    //ios::sync_with_stdio(false);
#ifndef ONLINE_JUDGE
    FILE *myfile;
    myfile = freopen("C:\\Users\\acm-14\\Desktop\\test\\b.in", "r", stdin);
    if (myfile == NULL)
        fprintf(stdout, "error on input freopen\n");
    FILE *outfile;
    outfile = freopen("C:\\Users\\acm-14\\Desktop\\test\\out.txt", "w", stdout);
    if (outfile == NULL)
        fprintf(stdout, "error on output freopen\n");
    long _begin_time = clock();
#endif
    smain();
#ifndef ONLINE_JUDGE
    long _end_time = clock();
    printf("time = %ld ms.", _end_time - _begin_time);
#endif
    return 0;
}


int n, m, k;
int h[10][10], v[10][10];
int ans[10];
int tot;
int check(int x) {
    int ret = 0;
    rep(i,1,n-x)
        rep(j, 1, n-x) {
        int nr = i, nc = j;
        int ok = 1;
        if (ok)rep(k, 1, x) { if (h[nr][nc])nc++; else ok = 0; }
        if (ok)rep(k, 1, x) { if (v[nr][nc])nr++; else ok = 0; }
        if (ok)rep(k, 1, x) { if (h[nr][nc-1])nc--; else ok = 0; }
        if (ok)rep(k, 1, x) { if (v[nr-1][nc])nr--; else ok = 0; }
        if (ok)ret++;

    }
    return ret;
}

void smain() {
    int kase = 0;
    int first = 1;
    while (cin >> n >> m) {
        if (first == 1)first = 0;
        else { cout << endl; puts("**********************************"); cout << endl; }
        mmm(h, 0); mmm(v, 0); mmm(ans, 0);
        while (m--) {

            char op;
            int r, c;
            cin >> op >> r >> c;
            if (op == 'H') {
                h[r][c] = 1;
            }
            else v[c][r] = 1;
            rep(i, 1, n) {
                ans[i]=check(i);
            }
        }
        printf("Problem #%d\n\n", ++kase);
        int fl = 0;
        rep(i, 1, n)if (ans[i])fl++;
        if (!fl)printf("No completed squares can be found.\n");
        else rep(i, 1, n)if (ans[i])printf("%d square (s) of size %d\n", ans[i], i);
        
        
    }
}
/*

*/