Investigating Div-Sum Property UVA - 11361

#include<bits/stdc++.h>
using namespace std;

#define rep(i,a,b) for(int i=a;i<b;i++)
typedef long long ll;
bool is_prime(int x){if(x<2)return false;int m=sqrt(x+0.5);rep(i,2,m+1)if(x%i==0)return false;return true;}


int a,b,k;

int bit[20];
int dp[20][10010][200];

int dfs(int pos,int limit,int sum_dig,int sum){
    if(pos==-1)  return (sum_dig==0)&&(sum==0);

    if(!limit&&dp[pos][sum][sum_dig]!=-1)return dp[pos][sum][sum_dig];
    int up=limit?bit[pos]:9;
    int ans=0;
    rep(i,0,up+1){
        ans+=dfs(pos-1,limit&&i==up,(sum_dig+i)%k,(sum*10+i)%k);
    }
    if(!limit)dp[pos][sum][sum_dig]=ans;
    return ans;
}

int solve(int x){
   // if(x==0)return 0;
    int cnt=0;
    int tmp=x;
    while(tmp){
        bit[cnt++]=tmp%10;
        tmp/=10;
    }
    return dfs(cnt-1,1,0,0);
}


int main(){
    int T;
    scanf("%d",&T);
    while(T--){
        memset(dp,-1,sizeof(dp));
        scanf("%d %d %d",&a,&b,&k);
        printf("%d\n",solve(b)-solve(a-1));
    }
    return 0;
}

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转载自blog.csdn.net/qq_36424540/article/details/81610237