leetcode 7.反转整数

给定一个 32 位有符号整数，将整数中的数字进行反转。

 1 class Solution:
 2     def reverse(self, x):
 3         """
 4         :type x: int
 5         :rtype: int
 6         """
 7         bool = False
 8         if x < 0:
 9             bool = True
10         if bool:
11             num = int("-"+str(x)[1:][::-1])
12         else:
13             num = int(str(x)[::-1])
14         
15         if -2 ** 31 <= num <= 2 ** 31 - 1:
16             return num
17         else:
18             return 0
19             
20             
21             
22