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建立视图和矩阵之间的对应关系,然后模拟
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define rep(i, x, y) for (int i = x; i < y; i++)
using namespace std;
const int maxn = 15;
int n;
char pos[maxn][maxn][maxn];
char view[6][maxn][maxn];
inline void input(char &c) {
do { c = getchar(); } while (c != '.' && (c < 'A' || c > 'Z'));
}
void get(int k, int i, int j, int len, int &x, int &y, int &z) {
if (k == 0) { x = len; y = j; z = i; }
else if (k == 1) { x = n - 1 - j; y = len; z = i; }
else if (k == 2) { x = n - 1 - len; y = n - 1 - j; z = i; }
else if (k == 3) { x = j; y = n - 1 - len; z = i; }
else if (k == 4) { x = n - 1 - i; y = j; z = len; }
else if (k == 5) { x = i; y = j; z = n - 1 - len; }
}
void solve() {
rep(i, 0, n) rep(k, 0, 6) rep(j, 0, n) input(view[k][i][j]);
rep(i, 0, n) rep(j, 0, n) rep(k, 0, n) pos[i][j][k] = '#';
rep(k, 0, 6) rep(i, 0, n) rep(j, 0, n) if (view[k][i][j] == '.') rep(p, 0, n) {
int x, y, z; get(k, i, j, p, x, y, z);
pos[x][y][z] = '.';
}
while (1) {
bool done = true;
rep(k, 0, 6) rep(i, 0, n) rep(j, 0, n) if (view[k][i][j] != '.') rep(p, 0, n) {
int x, y, z; get(k, i, j, p, x, y, z);
if (pos[x][y][z] == '.') continue;
if (pos[x][y][z] == '#') { pos[x][y][z] = view[k][i][j]; break; }
if (pos[x][y][z] == view[k][i][j]) break;
pos[x][y][z] = '.';
done = false;
}
if (done) break;
}
int ans = 0;
rep(i, 0, n) rep(j, 0, n) rep(k, 0, n) if (pos[i][j][k] != '.') ans++;
printf("Maximum weight: %d gram(s)\n", ans);
}
int main() {
while (~scanf("%d", &n) && n) solve();
return 0;
}