python3 list转化为嵌套字典

利用Python3的字典嵌套功能，把list转化为dict，从而降低时间复杂度。

list转化dict

trend_dict={}
for i in list_file:
i = json.loads(i)
if trend_dict.contains(i.get(‘title’)):

    if trend_dict.get(i.get('title').__contains__(i.get('time'))):
            trend_dict[i.get('title')][i.get('time')]=      max(i.get('hot'),trend_dict[i.get('title')][i.get('time')])
    elif len(trend_dict[i.get('title')]) <6:
        trend_dict[i.get('title')][i.get('time')]= i.get('hot')


else:
    trend_dict[i.get('title')]={} # hottop_dict[i.get('hottop')]是键，{}是值
    trend_dict[i.get('title')][i.get('time')]=i.get('hot')

取出dict中的值，用下标取

for i in trend_dict.keys():
print(i)
for j in trend_dict[i]:
print(j,trend_dict[i][j])