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For an array, for each element, find the value of the first smaller element before it. If not, then output it itself.
Example
Given arr = [2,3,6,1,5,5]
, return [2,2,3,1,1,1]
.
Explanation:
According to the meaning, find the first smaller element in front of each number.
Given arr = [6,3,1,2,5,10,9,15]
, return [6,3,1,1,2,5,5,9]
.
Explanation:
According to the meaning, find the first smaller element in front of each number.
class Solution {
public:
/**
* @param num: The arry you should handle
* @return: Return the array
*/
vector<int> getPreviousNumber(vector<int> &num) {
// Write your code here
stack<int> s;
vector<int> res;
for (int i = 0; i < num.size(); i++) {
while (!s.empty() && s.top() >= num[i]) {
s.pop();
}
if (s.empty()) {
res.push_back(num[i]);
} else {
res.push_back(s.top());
}
s.push(num[i]);
}
return res;
}
};