版权声明:版权归 你的pizza到了 所有,未经允许不可转载 https://blog.csdn.net/qq_38353993/article/details/82561874
1、案例分析
1)、将一副牌封装进入Map集合中,键为0-53的Integer数据,值为字符串
2)、洗牌:将Map集合的键放在List中,在使用Collections.shuffle()进行洗牌
3)、发牌:发给三个人,就是三个List加一个底牌的List
4)、看牌:将三人的List和底牌List的值进行排序(从大到小)
2、图解
3、代码实现:
public static void main(String[] args) {
//1)、封装牌
String[] colors = {"♥","♠","♦","♣"};//花色
String[] num = {"2","A","K","Q","J","10","9","8","7","6","5","4","3"};//数字
Map<Integer,String> pokerMap = new HashMap<>();//存放代表大小的键,代表牌面的值
int index = 0;//键
pokerMap.put(index++,"大王");//后++,先存入index=0,在对index++,牌中最大牌为大王,放在键为0的位置
pokerMap.put(index++,"小王");
for (String n:num) {
for (String c:colors) {//使用加强for循环对牌的花色和数字进行拼接
pokerMap.put(index++,c+n);
}
}
//2)洗牌:将Map集合的键放在List中,在使用Collections.shuffle()进行洗牌
//要将键存在List中是因为在洗牌时要使用Conllections.shuffle()方法,排序使用sort()方法
Set<Integer> key = pokerMap.keySet();
ArrayList<Integer> list = new ArrayList<>();
list.addAll(key);
Collections.shuffle(list);//利用shuffle()方法将list中元素的顺序打乱
//3)发牌:发给三个人,就是三个List加一个底牌的List
ArrayList<Integer> user1 = new ArrayList<>();
ArrayList<Integer> user2 = new ArrayList<>();
ArrayList<Integer> user3 = new ArrayList<>();
ArrayList<Integer> dipai = new ArrayList<>();
for (int i = 0; i < list.size(); i++) {
if (i>=list.size() - 3){
dipai.add(list.get(i));
}else {
if (i % 3 == 0){
user1.add(list.get(i));
}
if (i % 3 == 1){
user2.add(list.get(i));
}
if (i % 3 == 2){
user3.add(list.get(i));
}
}
}
//看牌:将三人的List和底牌List的值进行排序(从大到小)
Collections.sort(user1);
Collections.sort(user2);
Collections.sort(user3);
Collections.sort(dipai);
System.out.println("玩家1:"+ getPoker(user1,pokerMap));
System.out.println("玩家2:"+ getPoker(user2,pokerMap));
System.out.println("玩家3:"+ getPoker(user3,pokerMap));
System.out.println("底牌:"+ getPoker(dipai,pokerMap));
}
private static ArrayList<String> getPoker(ArrayList<Integer> user, Map<Integer, String> pokerMap) {
ArrayList<String> pokerList = new ArrayList<>();
for (int i = 0; i < user.size(); i++) {
pokerList.add(pokerMap.get(user.get(i)));
}
return pokerList;
}