1001 A+B Format(20 分)
Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where
The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
解析
第一次做英文的OJ,光读题理解题意就花了好长时间 (ノへ ̄、)
这题的要求就是把数字转换成每三位加一个逗号,
Code:
#include<cstdio>
#include<iostream>
#include<string>
using namespace std;
int main()
{
int num1, num2;
cin >> num1 >> num2;
num1 += num2;
if (num1<1000 && num1>-1000)
cout << num1;
else if (num1<1000000 && num1>-1000000)
printf("%d,%03d", num1 / 1000, abs(num1) % 1000);
else
printf("%d,%03d,%03d", num1 / 1000000,num1/1000-num1/1000000*1000, abs(num1) % 1000);
}