java.lang.NumberFormatException: Expected an int but was 4.3 at line 82 column 24 path $.results[1]. - 代码天地

java.lang.NumberFormatException: Expected an int but was 4.3 at line 82 column 24 path $.results[1].

其他 2018-09-18 12:08:59 阅读次数: 0

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转载自blog.csdn.net/Mr___Xu/article/details/81185754

java.lang.NumberFormatException: Expected an int but was 4.3 at line 82 column 24 path $.results[1].

java.lang.IllegalStateException: Expected BEGIN_ARRAY but was STRING at line 1 column 1 path $

java.lang.IllegalStateException: Expected BEGIN_ARRAY but was BEGIN_OBJECT at line 1 column 2 path $

java.lang.IllegalStateException: Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 38 path

解决：Expected BEGIN_OBJECT but was STRING at line 1 column 1 path $

Expected BEGIN_OBJECT but was STRING at line 4 column 1 path $ 错误积累

retrofit请求报错：Expected a string but was BEGIN_OBJECT at line 1 column 2 path $

【_ 記】Expected BEGIN_OBJECT but was STRING at line 1 column 33 path $.httpResponse

Cause: Expected a name but was STRING at line 1 column 100 path $[0].apkInfo.versionName

Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 2 path

java.lang.IllegalStateException: Expected BEGIN_OBJECT but was was STRING at line 1 column 1

Incorrect column count: expected 1, actual 24

HTTP Status 500 - /jsp/customer/edit.jsp (line: 82, column: 75) quote symbol expected

Gson 解析Json数据时候报错： Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 2 path $

调用 gson.fromJson(json, tClass)方法时，抛出异常_ com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected a string but was BEGIN_ARRAY at line 1 column 28 path $.errors

expected '<document start>', but found Scalar in 'reader', line 51, column 1:

java.lang.NumberFormatException: Invalid int: "0 "

java.lang.NumberFormatException: Invalid int: "296.0"

两步让Retrofit使用FastJson解析：解决返回String报错：Expected a string but was BEGIN_OBJECT at line 1 column 2 path

android retrofit End of input at line 1 column 1 path

Unterminated object at line 1 column 53 path $.date

java.lang.NumberFormatException: Invalid int: ""的解决方法

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