剑指Offer_编程题18:二叉树的镜像

题目:操作给定的二叉树,将其变换为源二叉树的镜像。

二叉树的镜像定义:源二叉树 
    	    8
    	   /  \
    	  6   10
    	 / \  / \
    	5  7 9 11
    	镜像二叉树
    	    8
    	   /  \
    	  10   6
    	 / \  / \
    	11 9 7  5

牛客网:链接

# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution:
    # 返回镜像树的根节点
    def Mirror(self, root):
        # write code here
        if root == None or (root.left == None and root.right == None):
            return False
        tmp = root.left
        root.left = root.right
        root.right = tmp

        if root.left:
            self.Mirror(root.left)
        if root.right:
            self.Mirror(root.right)

猜你喜欢

转载自blog.csdn.net/mengmengdajuanjuan/article/details/82893347