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中等难度题吧,求二叉排序树的最低公共祖先
注意:
1、测试点345测试数据比较大,函数在写的时候尽量避免递归操作,所有的递归操作改成while
2、我写了两个搜索函数,搜索功能一样,只是第二个搜索函数添加了LCA的判断操作(如果通过搜索两个值的所有祖先存到vector中之后再判断两个vector来找到LCA的话测试点4会一直超时)
#include <cstdio>
#include <iostream>
#include <set>
#include <vector>
#include <algorithm>
using namespace std;
struct TreeNode
{
int value;
TreeNode *left, *right;
TreeNode(const int x) :value(x), left(nullptr), right(nullptr) {}
};
TreeNode *root = nullptr;
void insertBST(int value)
{
if (root == nullptr)root = new TreeNode(value);
TreeNode *node = root;
TreeNode *lastNode = root;
bool leftOrRight;//left:true;right:false
while (node != nullptr)
{
if (value < node->value)
{
lastNode = node;
node = node->left;
leftOrRight = true;
}
else
{
lastNode = node;
node = node->right;
leftOrRight = false;
}
}
if(leftOrRight)
lastNode->left = new TreeNode(value);
else
lastNode->right = new TreeNode(value);
}
int findBST(TreeNode *node, const int &value, vector<int> &path)
{
while (node != nullptr)
{
path.push_back(node->value);
if (node->value == value)
return 1;
if(value < node->value)
node = node->left;
else
node = node->right;
}
return -1;
}
int LCA;
int findBST111(TreeNode *node, const int &value, vector<int> &path)
{
int pathIndex = 0;
bool ifStop = false;
LCA = node->value;
while (node != nullptr)
{
if (!ifStop)
{
if(node->value != path[pathIndex])
{
ifStop = true;
continue;
}
LCA = node->value;
if (pathIndex < path.size() - 1)
pathIndex++;
}
if (node->value == value)
return 1;
if (value < node->value)
node = node->left;
else
node = node->right;
}
return -1;
}
int main()
{
int Mtest, Nnode;
scanf_s("%d%d", &Mtest, &Nnode);
for(int i = 0; i < Nnode; i++)
{
int value;
scanf_s("%d", &value);
insertBST(value);
}
for (int i = 0; i < Mtest; ++i)
{
int node1, node2;
scanf_s("%d%d", &node1, &node2);
vector<int>Path1;
int findRes1 = findBST(root, node1, Path1), findRes2 = findBST111(root, node2, Path1);
if(findRes1 == -1 && findRes2 == -1)
{
cout << "ERROR: " << node1 << " and " << node2 << " are not found." << endl;
continue;
}else if(findRes1 == -1 && findRes2 == 1)
{
cout << "ERROR: " << node1 << " is not found." << endl;
continue;
}else if(findRes1 == 1 && findRes2 == -1)
{
cout << "ERROR: " << node2 << " is not found." << endl;
continue;
}
if (LCA == node1)
{
cout << node1 << " is an ancestor of " << node2 << "." << endl;
}else if(LCA == node2)
{
cout << node2 << " is an ancestor of " << node1 << "." << endl;
}else
{
cout << "LCA of " << node1 << " and " << node2 << " is " << LCA << "." << endl;
}
}
}