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树的子结构 java
题目描述
输入两棵二叉树A,B,判断B是不是A的子结构。(ps:我们约定空树不是任意一个树的子结构)
代码1:
/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
public class Solution {
public boolean HasSubtree(TreeNode root1,TreeNode root2) {
boolean flag = false;
if(root1 != null && root2 != null){
if(root1.val == root2.val){
flag = getCompare(root1, root2);
}
if(!flag){
flag = HasSubtree(root1.left, root2);
}
if(!flag){
flag = HasSubtree(root1.right, root2);
}
}
return flag;
}
public boolean getCompare(TreeNode root1,TreeNode root2){
if(root2 == null){
return true;
}
if(root1 == null){
return false;
}
if(root1.val != root2.val){
return false;
}
return getCompare(root1.left, root2.left) && getCompare(root1.right, root2.right);
}
}
代码2:
public class Solution {
public boolean HasSubtree(TreeNode root1,TreeNode root2) {
boolean flag = false;
if(root1 != null && root2 != null){
if(root1.val == root2.val){
flag = getCompare(root1, root2);
}
if(!flag){
flag = HasSubtree(root1.left, root2);
}
if(!flag){
flag = HasSubtree(root1.right, root2);
}
}
return flag;
}
private boolean getCompare(TreeNode root1,TreeNode root2){
boolean flag = false;
if(root2 == null){
flag = true;
}
if(root1 != null && root2 != null && root1.val == root2.val){
flag = getCompare(root1.left, root2.left) && getCompare(root1.right, root2.right);
}
return flag;
}
}