点击打开链接
class Solution {
public:
double Power(double base, int exponent) {
double sum=1.0;
if(exponent>0){
for(int i=1;i<=exponent;i++)
sum*=base;
}else
{
for(int i=1;i<=abs(exponent);i++)
sum*=base;
sum=1/sum;
}
return sum;
}
};
主要考虑负数情况,基本无难度