error:You must feed a value for placeholder tensor 'momentum' with dtype float - 代码天地

error:You must feed a value for placeholder tensor 'momentum' with dtype float

其他 2018-12-03 09:51:04 阅读次数: 0

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转载自blog.csdn.net/Z609834342/article/details/83616385

error:You must feed a value for placeholder tensor 'momentum' with dtype float

You must feed a value for placeholder tensor 'Placeholder_1' with dtype float and shape [?,10]

Tensorflow: You must feed a value for placeholder tensor 'inputs/y_input' with dtype float and shape

InvalidArgumentError (see above for traceback): You must feed a value for placeholder tensor 'Y' with dtype float

坑之 You must feed a value for placeholder tensor ‘label_input‘ with dtype float and shape

INVALID_ARGUMENT: You must feed a value for placeholder tensor ‘inputs‘ with dtype float and shape

InvalidArgumentError: You must feed a value for placeholder tensor 'xxx' with dtype xxx and shape xx

tl.layers.DropoutLayer引发的“ You must feed a value for placeholder tensor 'Placeholder' ”问题及解决方法

merged = tf.summary.merge_all()引起的出错：You must feed a value for placeholder tensor ‘input/y-input‘

Tensorflow报错：placeholder tensor 'Placeholder_1' with dtype float

tensorflow.python.framework.errors_impl.InvalidArgumentError: You must feed a value for placeholder报

tensorflow.python.framework.errors_impl.InvalidArgumentError: You must feed a value for placeholder

ValueError: Cannot feed value of shape (1,) for Tensor u'Placeholder:0', which has shape '(1, 1)'

ValueError: Cannot feed value of shape (784,) for Tensor 'Placeholder:0', which has shape '(?, 784)'

已解决ValueError: Cannot feed value of shape (1, 10, 4) for Tensor ‘Placeholder:0‘, which has shape ‘(?

ValueError: Cannot feed value of shape (2,) for Tensor u'Placeholder_2:0', which has shape '(1, 2)'

对tensorflow中的tensor、placeholder及feed_dict的理解

input_tensor alone dtype must be string or integer

tensorlayer中dropoutlayer层的feed value for placeholder问题

TypeError: The value of a feed cannot be a tf.Tensor object.

TensorFlow 报错 TypeError: The value of a feed cannot be a tf.Tensor object

ValueError: Tensor Tensor("mrcnn_detection/PyFunc:0", dtype=float32) is not an element of this graph

ValueError: Tensor Tensor(“...”, shape=(?, 6), dtype=float32) is not an element of this graph.解决方法

Tensor Tensor("dense_2/Softmax:0", shape=(?, 192), dtype=float32) is not an element of this graph

Tensor Tensor("predictions/Softmax:0",shape=(?,4),dtype=float32) is not an element of this graph

TypeError: The value of a feed cannot be a tf.Tensor object. Acceptable feed values include Python s

tensorboard--[[Node: inputs/x_input = Placeholder[dtype=DT_FLOAT, shape=[], _device="/job:localhost

ValueError:Tensor("dense_1/Softmax:0", shape=(?, 3), dtype=float32) is not an element of this graph

Could not compute output Tensor(“activation/Identity:0“, shape=(None, 1), dtype=float32)

记录：tensoflow改错TypeError: Cannot interpret feed_dict key as Tensor: Can not convert a float into a Te

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