A + B Problem Too【HDU - 2101】

A + B Problem Too问题

水题，不多说先上题目

题目

This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.

Time limit	Memory limit	OS	Source
1000 ms	32768 kB	Windows	HDU 2007-6 Programming Contest

Input

Each line will contain two integers A and B. Process to end of file.

Output

For each case, if(A+B)%86=0,output yes in one line,else output no in one line.

Example

input	output
1 1	no
8600 8600	yes

问题链接：HDU - 2101

问题描述

输入两个数据，求它们的和，并判断和能不能被86整除，如果能就输出yes，不能则输出no。

问题分析

首先获得用户的两个输入，然后求两数的和，将和存于一变量中，然后再用该变量除以86求余数，如果余数得0则输出yes，其他数则输出no。在其外套上一层while循环用于重复程序。

AC通过的C++语言程序代码如下：

#include<iostream>
using namespace std;
int main()
{
    int a, b, r;
    while (cin >> a >> b)
    {
        r = a + b;
        if (r % 86 == 0)
            cout << "yes" << endl;
        else
            cout << "no" << endl;
    }
}