【LeetCode】23. Merge k Sorted Lists(C++)

地址:https://leetcode.com/problems/merge-k-sorted-lists/

题目:

Merge k k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.

Example:
在这里插入图片描述

理解:

合并k个有序链表。想到了外部排序里面的败者数,其本质也是一个堆。因此,把k个链表的头结点加到一个小根堆里,然后把堆顶弹出,并把堆顶的下一个结点加入。

实现:

class Solution {
public:
	ListNode* mergeKLists(vector<ListNode*>& lists) {
		auto comp = [](const ListNode* lhs, const ListNode* rhs) {return lhs->val > rhs->val; };
		priority_queue<ListNode*, vector<ListNode*>, decltype(comp)> q(comp);
		for (auto p : lists)
			if (p)
				q.push(p);
		if (q.empty()) return nullptr;

		ListNode* head = q.top();
		q.pop();
		if (head->next)
			q.push(head->next);
		ListNode* p = head;
		while (!q.empty()) {
			p->next = q.top();
			q.pop();
			p = p->next;
			if (p->next) q.push(p->next);
		}
		return head;
	}
};

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转载自blog.csdn.net/Ethan95/article/details/85195403
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