1.练习-黄金分割点
- 寻找某两个数相除，其结果 离黄金分割点 0.618最近
- 分母和分子不能同时为偶数
- 分母和分子 取值范围在[1-20]
package review2;
public class Test1 {
public static void main(String[] args) {
//黄金分割点
float breakPoint = 0.618f;
int fenzi = 1,fenmu = 1;//分子，分母
float minDiff = 100;
for(int i = 1; i < 20; i++) {
for(int j =1;j < 20; j++) {
if(i%2 == 0 && j%2 == 0) continue;
float result = (float)i/j;
//差值
float diff = result-breakPoint;
//取绝对值
diff = diff < 0 ? 0-diff:diff;
if(diff < minDiff) {
minDiff = diff;
fenzi = i;
fenmu = j;
}
}
}
System.out.println("离黄金分割点(" + breakPoint + ")最近的两个数相除是:" +fenzi+"/"+fenmu+"="+(float)fenzi/fenmu);
}
}
2.练习-水仙花数
水仙花数定义：
1. 一定是3位数
2. 每一位的立方，加起来恰好是这个数本身，比如153=1*1*1+5*5*5+3*3*3
目的：寻找1000以内所有的水仙花数
package review2;
public class Test2 {
public static void main(String[] args) {
int flower = 100;
for(;flower < 1000; flower++) {
//中间变量temp
int temp = flower;
//个位数
int i = temp%10;
temp = temp/10;
//十位数
int j = temp%10;
temp = temp/10;
//百位数
int k = temp;
float result = i*i*i+j*j*j+k*k*k;
if(result == flower) {
System.out.println("水仙花数："+flower);
}
}
}
}
3.练习-小学算术题
package review2;
public class Test3 {
public static void main(String[] args) {
for (int a = 0; a <= 100; a++) {
for (int b = 0; b <= 100; b++) {
for (int c = 0; c <= 100; c++) {
for (int d = 0; d <= 100; d++) {
if(a+b == 8 && c-d == 6 && a+c == 14 && b+d == 10) {
System.out.println("a="+a+"\nb="+b+"\nc="+c+"\nd="+d);
}
}
}
}
}
}
}
4.练习-数组最小值
首先创建一个长度是5的数组，然后给数组的每一位赋予随机整数，通过for循环，遍历数组，找出最小的一个值出来0-100的 随机整数的获取办法有多种，下面是参考办法之一: (int) (Math.random() * 100)
Math.random() 会得到一个0-1之间的随机浮点数，然后乘以100，并强转为整型即可。
package review2;
public class Test4 {
public static void main(String[] args) {
int[] a = new int[5];
int min =101;
for(int i = 0;i < a.length; i++) {
a[i] = (int) (Math.random()*100);
System.out.println(a[i]);
}
for(int j = 0; j < a.length; j++) {
if(a[j] < min) {
min = a[j];
}
}
System.out.println("最小值："+min);
}
}