NCURSES程序设计之魔数方阵

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魔数方阵简单的说,就是将连续整数1,2,3....,n 的数字,依特别之顺序,排在方阵里.使每一行的数,每一列的数或对角线位置的数各自相加,所得的和皆均为相同.

#include <curses.h>
#include <stdlib.h>


#define STARTX 9
#define STARTY 3
#define WIDTH  6
#define HEIGHT 4


#define TRACE_VALUE TRACE_MAXIMUM 


void board( WINDOW *win, int starty, int startx, int lines, int cols, 
int tile_width, int tile_height);
void magic(int **, int);
void print(int **, int);
void magic_board(int **a,int n);


int main(int argc, char *argv[])
{

int **a,n,i;


if(argc != 2)
{ printf("Usage: %s <magic sqaure order>\n", argv[0]);
exit(0);
}
n = atoi(argv[1]);
if(n % 2 == 0)
{ printf("Sorry !!! I don't know how to create magic square of even order\n");
printf("The order should be an odd number\n");
exit(0);
}
a = (int **) malloc(n * sizeof(int*));
for(i = 0;i < n;++i)
a[i] = (int *)malloc(n * sizeof(int));


magic(a,n);

initscr();
curs_set(0);
noecho();
magic_board(a,n);
getch();
endwin();


return;
}


void magic(int **a, int n)
{
int i,j,k;
int row,col;
for(i = 0;i < n;++i)
for(j = 0;j < n;++j)
a[i][j] = -1;
row = 0;
col = n / 2;


k = 1;
a[row][col] = k;

while(k != n * n)
{
if(row == 0 && col != n - 1)
{ row = n - 1;
col ++;
a[row][col] = ++k;
}
else if(row != 0 && col != n - 1)
{ if(a[row - 1][col + 1] == -1)
{ row --;
col ++;
a[row][col] = ++k;
}
else
{
row ++;
a[row][col] = ++k;
}
}
else if(row != 0 && col == n - 1)
{
row --;
col = 0;
a[row][col] = ++k;
}
else if(row == 0 && col == n - 1)
{ row ++;
a[row][col] = ++k;
}

}
return;
}


void print(int **a,int n)
{ int i,j;
int x,y;
x = STARTX;
y = STARTY;
mvprintw(1,30,"MAGIC SQUARE");
for(i = 0;i < n;++i)
{ for(j = 0;j < n;++j)
{ mvprintw(y,x,"%d",a[i][j]);
if(n > 9)
x += 4;
else
x += 6;
}
x = STARTX;
if(n > 7)
y += 2;
else
y += 3;
}
refresh();
}
void board(WINDOW *win, int starty, int startx, int lines, int cols, 
  int tile_width, int tile_height)
{ int endy, endx, i, j;

endy = starty + lines * tile_height;
endx = startx + cols  * tile_width;

for(j = starty; j <= endy; j += tile_height)
for(i = startx; i <= endx; ++i)
mvwaddch(win, j, i, ACS_HLINE);
for(i = startx; i <= endx; i += tile_width)
for(j = starty; j <= endy; ++j)
mvwaddch(win, j, i, ACS_VLINE);
mvwaddch(win, starty, startx, ACS_ULCORNER);
mvwaddch(win, endy, startx, ACS_LLCORNER);
mvwaddch(win, starty, endx, ACS_URCORNER);
mvwaddch(win, endy, endx, ACS_LRCORNER);
for(j = starty + tile_height; j <= endy - tile_height; j += tile_height)
{ mvwaddch(win, j, startx, ACS_LTEE);
mvwaddch(win, j, endx, ACS_RTEE);
for(i = startx + tile_width; i <= endx - tile_width; i += tile_width)
mvwaddch(win, j, i, ACS_PLUS);
}
for(i = startx + tile_width; i <= endx - tile_width; i += tile_width)
{ mvwaddch(win, starty, i, ACS_TTEE);
mvwaddch(win, endy, i, ACS_BTEE);
}
wrefresh(win);
}


void magic_board(int **a,int n)
{ int i,j, deltax, deltay;
int startx, starty;


starty = (LINES - n * HEIGHT) / 2;
startx = (COLS  - n * WIDTH) / 2;
board(stdscr, starty, startx, n, n, WIDTH, HEIGHT);
deltay = HEIGHT / 2;
deltax = WIDTH  / 2;
for(i = 0;i < n; ++i)
for(j = 0; j < n; ++j)
mvprintw(starty + j * HEIGHT + deltay,
startx + i * WIDTH  + deltax,
"%d", a[i][j]);
}

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转载自blog.csdn.net/wangjiaweiwei/article/details/75608820