Bug: TypeError: sendall() argument 1 must be string or buffer, not dict - 代码天地

Bug: TypeError: sendall() argument 1 must be string or buffer, not dict

其他 2019-01-04 08:30:51 阅读次数: 0

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转载自blog.csdn.net/Da___Vinci/article/details/85159810

Bug: TypeError: sendall() argument 1 must be string or buffer, not dict

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