Java8的groupBy实现集合的分组,类似Mysql的group by分组功能,注意得到的是一个map
对集合按照单个属性分组
case1:
List<String> items = Arrays.asList("apple", "apple", "banana", "apple", "orange", "banana", "papaya"); // 分组 Map<String, List<String>> result1 = items.stream().collect( Collectors.groupingBy( Function.identity() ) ); //{papaya=[papaya], orange=[orange], banana=[banana, banana], apple=[apple, apple, apple]} System.out.println(result1); // 分组计数 Map<String, Long> result2 = items.stream().collect( Collectors.groupingBy( Function.identity(), Collectors.counting() ) ); // {papaya=1, orange=1, banana=2, apple=3} System.out.println(result2); Map<String, Long> finalMap = new LinkedHashMap<>(); //分组, 计数和排序 result2.entrySet().stream() .sorted(Map.Entry.<String, Long>comparingByValue().reversed()) .forEachOrdered(e -> finalMap.put(e.getKey(), e.getValue())); // {apple=3, banana=2, papaya=1, orange=1} System.out.println(finalMap);
case2:
User user1 = new User("zhangsan", "beijing", 10); User user2 = new User("zhangsan", "beijing", 20); User user3 = new User("lisi", "shanghai", 30); List<User> list = new ArrayList<User>(); list.add(user1); list.add(user2); list.add(user3); Map<String, List<User>> collect = list.stream() .collect( Collectors.groupingBy( User::getName/*, Collectors.counting()*/ ) ); //{lisi=[User{age=30, name='lisi', address='shanghai'}], // zhangsan=[User{age=10, name='zhangsan', address='beijing'}, User{age=20, name='zhangsan', address='beijing'}]} System.out.println(collect);