ACM训练2

George and Accommodation
Problem Description
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has n rooms in total. At the moment the i-th room has pi people living in it and the room can accommodate qi people in total (pi ≤ qi). Your task is to count how many rooms has free place for both George and Alex.
INPUT
The first line contains a single integer n (1 ≤ n ≤ 100) — the number of rooms.
The i-th of the next n lines contains two integers pi and qi (0 ≤ pi ≤ qi ≤ 100) — the number of people who already live in the i-th room and the room’s capacity.
OUTPUT
Print a single integer — the number of rooms where George and Alex can move in.
问题连接:https://vjudge.net/problem/CodeForces-467A
问题分析:建立两个整形数组,一个记录房间容量一个记录房间已住人数和一个变量统计有两个以上空位的房间数。
AC通过的代码:

#include <iostream>
using namespace std;
int main()
{
 int a[100] = { 0 }, b[100] = { 0 }, n = 0, sum = 0;
 cin >> n;
 for (int i = 0; i < n; i++)
 {
  cin >> a[i] >> b[i];
 }
 for (int i = 0; i < n; i++)
 {
  if (b[i] - a[i] >= 2)sum++;
 }
 cout << sum << endl;
}

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转载自blog.csdn.net/weixin_43966635/article/details/84844370