交换两个数组的内容(数组一样大)

 
 
#include <stdio.h>
#include <stdlib.h>
int main()
{
	int arr1[] = { 1, 2, 3, 4 }; 
	int arr2[] = { 5, 6, 7, 8 };
	int arr3[] = { 0, 0, 0, 0 };                 //建立一个空数组用来过渡
	int i = 0;
		printf("交换前第一个数组值为:");
		for (i = 0; i < sizeof (arr1) / sizeof (arr1[0]); i++)
		{
			printf("%d ", arr1[i]);
		}
		printf("\n");                     //打印第一个数组更改之前的值
		printf("交换前第二个数组值为:");
		for (i = 0; i < sizeof (arr1) / sizeof (arr1[0]); i++)
		{
			printf("%d ", arr2[i]);
		}
		printf("\n");                     //打印第一个数组更改之前的值
	for (i = 0; i < sizeof (arr1) / sizeof (arr1[0]); i++)
	{
		arr3[i] = arr1[i];
		arr1[i] = arr2[i];
		arr2[i] = arr3[i];              //利用空数组进行组内内容逐一交换

	}
	printf("交换前第一个数组值为:");
	for (i = 0; i < sizeof (arr1) / sizeof (arr1[0]); i++)
	{
		printf("%d ", arr1[i]);        
	}
	printf("\n");                           //打印第一个数组更改之后的值
	printf("交换前第二个数组值为:");
	for (i = 0; i < sizeof (arr1) / sizeof (arr1[0]); i++)
	{
		printf("%d ", arr2[i]);
	}
	printf("\n");                         //打印第一个数组更改之后的值
	system("pause");
		return 0;
}

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转载自blog.csdn.net/higher_and/article/details/79673240