PHP 判断是否包含在某个字符串中

PHP 判断是否包含在某个字符串中

1.用strpos函数,查找字符首次出现的位置,如果不存在则会返回false
$str= ‘abc’;
$needle= ‘e’;
p o s = s t r p o s ( pos = strpos( str, $needle);
2.用strstr函数查找字符在字符串中首次出现,并返回字符出现开始的位置至结束的字符串
$email = ‘[email protected]’;
d o m a i n = s t r s t r ( domain = strstr( email, ‘@’);
3.用explode分割字符串,如果返回的数组长度大于一则表示存在
$str= ‘abc’;
$needle = ‘E’;//判断是否包含a这个字符
t m p a r r a y = e x p l o d e ( tmparray = explode( needle,$str);
4.用in_array检查数组中是否存在某个值
// bool in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] )
//in_array()例子
o s = a r r a y ( " M a c " , " N T " , " I r i x " , " L i n u x " ) ; i f ( i n a r r a y ( " I r i x " , os=array("Mac","NT","Irix","Linux"); if(in_array("Irix", os)){
echo “Got Irix”;
}
if(in_array(“mac”,$os)){
echo “Got mac”;
}
//第二个条件失败,因为in_array()是区分大小写的 所以只输出Got Irix
//in_array() 严格类型检查例子
$a = array(‘1.10’, 12.4, 1.13);
if (in_array(‘12.4’, $a, true)) {
echo “‘12.4’ found with strict check\n”;
}
if (in_array(1.13, $a, true)) {
echo “1.13 found with strict check\n”;
}
//程序会输出1.13 found with strict check
//in_array()中数组作为needle
$a = array(array(‘p’, ‘h’), array(‘p’, ‘r’), ‘o’);
if (in_array(array(‘p’, ‘h’), $a)) {
echo “‘ph’ was found\n”;
}
if (in_array(array(‘f’, ‘i’), $a)) {
echo “‘fi’ was found\n”;
}
if (in_array(‘o’, $a)) {
echo “‘o’ was found\n”;
}
//程序会输出
//‘ph’ was found
//‘o’ was found

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转载自blog.csdn.net/ahaotata/article/details/86153782
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