大一寒假训练十一(简单几何)(未完待续)

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nefu 823 计算内积

#include <bits/stdc++.h>
using namespace std;
long long a[100010];
long long b[100010];
int main()
{
    long long n,i,s;
    while(cin>>n)
    {
        for(i=1;i<=n;i++)
            cin>>a[i];
        for(i=1;i<=n;i++)
            cin>>b[i];
        s=0;
        for(i=1;i<=n;i++)
            s=s+a[i]*b[i];
        printf("%lld\n",s);
    }
    return 0;
}

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转载自blog.csdn.net/ljw_study_in_CSDN/article/details/88084707