1:第一种处理方法https://github.com/ralfstx/minimal-json
首先maven引入
<dependency>
<groupId>com.eclipsesource.minimal-json</groupId>
<artifactId>minimal-json</artifactId>
<version>0.9.4</version>
</dependency>
定义jsob
String sss = "{\"items\":[{\"xm\":\"张三\",\"bz\":\"学生\",\"nl\":\"18\"}]}";
JsonArray item = Json.parse(sss).asObject().get("items").asArray();
System.out.println("==value==="+item);
for (JsonValue i : item) {
String value = i.asObject().getString("xm", "");
System.out.println("==value==="+value);//取出来就是"张三"
}
2:第二种方法:
try{
JsonNode jsonNode = JsonUtils.jsonToJsonNode(sss).get("items");
System.out.println("=====value====="+jsonNode.get(0).get("xm").asText());//取出来就是"张三"
}catch (IOException e){
e.printStackTrace();
}
JsonUtils如下:
public class JsonUtils {
/**
* 将字符串转成JsonNode,允许斜杠等字符串
*/
public static JsonNode jsonToJsonNode(String json) throws IOException {
ObjectMapper mapper = new ObjectMapper();
// 允许反斜杆等字符
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_CONTROL_CHARS,true);
//允许单引号
mapper.configure(JsonParser.Feature.ALLOW_SINGLE_QUOTES,true);
return mapper.readValue(json, JsonNode.class);
}
public static <T> String objectToJson(Object object, Class<T> cls)throws Exception {
ObjectMapper mapper = new ObjectMapper();
mapper.registerSubtypes(cls);
String reqJson = mapper.writeValueAsString(object);
return reqJson;
}
/**
* 将字符串转成实体类,允许斜杠等字符串
*/
public static <T> T jsonToEntity(String json, Class<T> clazz) throws IOException {
ObjectMapper mapper = new ObjectMapper();
// 允许反斜杆等字符
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_CONTROL_CHARS,true);
return mapper.readValue(json, clazz);
}
}
java解析json字符串总结
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转载自amos-franck.iteye.com/blog/2344878
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