七段数码管的绘制 python

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1、问题分析：turtle ——>七段数码管绘制（时间等）

2、基本思路

-步骤一：绘制单个数字对应的数码管

-步骤二;获得一串数字，恢只对应的数码管

-步骤三：获取当前系统时间，绘制对应的数码管

-使用time库获得系统当前时间

-增加年月日标记

-年月日颜色不同

代码如下：

import turtle,time
def drawGap():#绘制数码管间隔
    turtle.penup()
    turtle.fd(5)
def drawLine(draw):#绘制单段数码管
    drawGap()
    turtle.pendown() if draw else turtle.penup()#true画笔落下
    turtle.fd(40)
    drawGap()
    turtle.right(90)
def drawDight(dight):#根据数字绘制七段数码管
    drawLine(True) if dight in [2, 3, 4, 5, 6, 8, 9] else drawLine(False)
    drawLine(True) if dight in [0, 1, 3, 4, 5, 6, 7, 8, 9] else drawLine(False)
    drawLine(True) if dight in [0, 2, 3, 5, 6, 8, 9] else drawLine(False)
    drawLine(True) if dight in [0, 2, 6, 8] else drawLine(False)
    turtle.left(90)
    drawLine(True) if dight in [0, 4, 5, 6, 8, 9] else drawLine(False)
    drawLine(True) if dight in [0, 2, 3, 5, 6, 7, 8, 9] else drawLine(False)
    drawLine(True) if dight in [0, 1, 2, 3, 4, 7, 8, 9] else drawLine(False)
    turtle.left(180)
    turtle.penup()
    turtle.fd(20)
def drawDate(date):#data为日期，格式为'%Y-%m=%d+'
    turtle.pencolor("red")
    '''for i in date:
        drawDight(eval(i))   '''
    for i in date:
        if i == '-':
            turtle.write('年',font=("Arial",19,"normal"))
            turtle.pencolor("green")
            turtle.fd(40)
        elif i =='=':
            turtle.write('月', font=("Arial", 19, "normal"))
            turtle.pencolor("blue")
            turtle.fd(40)
        elif i =='+':
            turtle.write('日', font=("Arial", 19, "normal"))
        else:
            drawDight(eval(i))

def main():
    turtle.setup(800,350,200,200)
    turtle.penup()
    turtle.fd(-300)
    turtle.pensize(5)
    #drawDate('20190227')
    drawDate(time.strftime('%Y-%m=%d+',time.gmtime()))
    turtle.hideturtle()
    turtle.done()
main()

运行：

扩展：

倒计时、小数等