【C练】写代码可以在整型有序数组中查找想要的数字, 找到了返回下标,找不到返回-1.(折半查找)

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
	int arr[5] = {1,3,5,7,9};
	int to_find = 0;
	int left = 0;
	int right = sizeof(arr) / sizeof(arr[0])-1;
	while (left <= right)
	{
          int mid = (left + right) / 2;
          if (arr[mid] < to_find)
	     {
		   left = mid + 1;
	     }
          else if (arr[mid] > to_find)
	     {
		   right = mid - 1;
	     }
          else
	     {
		   printf("找到了,下标为:%d\n", mid);
	           break;
	     }
        }
	if (left > right)
	{
		printf("没找到!");
	}
	printf("\n");
	system("pause");
	return 0;
}

定义一个有序数组,设定它的左右下标和中间下标mid。每次进行折半查找,比较查找的数和中间的数,若查找的数比mid大,则左下标等于mid-1,若查找的数比mid小,则右下标等于mid+1。若查找的数等于mid,则break。 

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转载自blog.csdn.net/LXL7868/article/details/88776800
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