将给定的n个整数从大到小排序后输出。

#include <iostream>
using namespace std;


int main(int argc, char *argv[])
{
	
	int n;
	cin >> n;
	int *a = new int[n];
	for (int i = 0; i < n; i++)
	{
		cin >> a[i];
	}
	int tmp;
	for (int i = 0; i < n; i++)
	{
		for (int j = n - 1; j > i; j--)
		{
			if (a[j] > a[j-1])
			{
				tmp = a[j];
				a[j] = a[j - 1];
				a[j - 1] = tmp;
			}
		}
	}
	for (int i = 0; i < n; i++)
	{
		cout << a[i];
	}


	return 0;
}

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转载自blog.csdn.net/xbpalyer/article/details/88752249