#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
int n;
cin >> n;
int *a = new int[n];
for (int i = 0; i < n; i++)
{
cin >> a[i];
}
int tmp;
for (int i = 0; i < n; i++)
{
for (int j = n - 1; j > i; j--)
{
if (a[j] > a[j-1])
{
tmp = a[j];
a[j] = a[j - 1];
a[j - 1] = tmp;
}
}
}
for (int i = 0; i < n; i++)
{
cout << a[i];
}
return 0;
}
将给定的n个整数从大到小排序后输出。
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转载自blog.csdn.net/xbpalyer/article/details/88752249
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