版权声明:看看就好,如需转载,注明一下出处 https://blog.csdn.net/sinat_34337520/article/details/89016514
Description
企业发放的奖金根据利润提成。利润低于或等于100000元的,奖金可提10%;
利润高于100000元,低于200000元(100000<I≤200000)时,低于100000元的部分按10%提成,高于100000元的部分,可提成 7.5%;
200000<I≤400000时,低于200000元部分仍按上述办法提成,(下同),高于200000元的部分按5%提成;
400000<I≤600000元时,高于400000元的部分按3%提成;600000<I≤1000000时,高于600000元的部分按1.5%提成;
I>1000000时,超过1000000元的部分按1%提成。从键盘输入当月利润I,求应发奖金总数。
Input
一个整数,当月利润。
Output
一个整数,奖金。
Sample Input
900
Sample Output
90
HINT
用Switch要比用if的看起来更清晰。
#include <stdio.h>
#include <stdlib.h>
int main()
{
int I, b, b1, b2, b3, b4, b5;
scanf("%d", &I);
b1 = 100000 * 0.1;
b2 = (200000-100000) * 0.075;
b3 = (400000-200000) * 0.05;
b4 = (600000-400000) * 0.03;
b5 = (1000000-600000) * 0.015;
if(I<=100000)
b = I * 0.1;
else if(I<=200000)
b = b1 + (I-100000)*0.075;
else if(I<=400000)
b = b1 + b2 + (I-200000)*0.05;
else if(I<=600000)
b = b1 + b2 + b3 + (I-400000)*0.03;
else if(I<=1000000)
b = b1 + b2 + b3 + b4 + (I-600000)*0.015;
else
b = b1 + b2 + b3 + b4 + b5 + (I-1000000)*0.01;
printf("%d", b);
return 0;
}
#include <stdio.h>
#include <stdlib.h>
//版本2:switch
int main()
{
int I, b, b1, b2, b3, b4, b5;
scanf("%d", &I);
b1 = 100000 * 0.1;
b2 = (200000-100000) * 0.075;
b3 = (400000-200000) * 0.05;
b4 = (600000-400000) * 0.03;
b5 = (1000000-600000) * 0.015;
switch(I/100000)
{
case 0:
b = I * 0.1;
break;
case 1:
b = b1 + (I-100000)*0.075;
break;
case 2:
case 3:
b = b1 + b2 + (I-200000)*0.05;
break;
case 4:
case 5:
b = b1 + b2 + b3 + (I-400000)*0.03;
break;
case 6:
case 7:
case 8:
case 9:
b = b1 + b2 + b3 + b4 + (I-600000)*0.015;
break;
default:
b = b1 + b2 + b3 + b4 + b5 + (I-1000000)*0.01;
break;
}
printf("%d", b);
return 0;
}