Ruby通过Luhn算法验证信用卡卡号的有效性

def luhn(code)
  s1 = s2 = 0
  code.to_s.reverse.chars.each_slice(2) do |odd, even|
    s1 += odd.to_i
  
    double = even.to_i * 2
    double -= 9 if double >= 10
    s2 += double
  end
  (s1 + s2) % 10 == 0
end
  
[49927398716, 49927398717, 1234567812345678, 1234567812345670].each do |n|
  p [n, luhn(n)]
end
 


运行结果如下

[49927398716, true]
[49927398717, false]
[1234567812345678, false]
[1234567812345670, true]

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转载自debbbbie.iteye.com/blog/1958496