Java多线程实现简单的售票程序

设计一个多线程程序如下:设计一个火车售票模拟程序。假如火车站要有100张火车票要卖出,现在有5个售票点同时售票,用5个线程模拟这5个售票点的售票情况

1、要求打印出每个售票点所卖出的票号

2、各售票点不能售出相同票号的火车票

package com.hebust.java.third;

 

import java.util.Random;

 

public class SaleTicket implements Runnable {

 

public int total;

public int count;

 

public SaleTicket() {

total = 100;

count = 0;

}

 

public void run() {

while (total > 0) {

synchronized (this) {

if(total > 0) {

try {

//Thread.sleep(800);

Thread.sleep(new Random().nextInt(1000));

} catch (InterruptedException e) {

e.printStackTrace();

}

count++;

total--;

 

System.out.println(Thread.currentThread().getName() + "\t当前票号:" + count);

}

}

}

 

}

 

public static void main(String[] args) {

SaleTicket st = new SaleTicket();

for(int i=1; i<=5; i++) {

new Thread(st, "售票点" + i).start();

}

}

}

 

第二种方法

public class MyThread4 extends Thread  
{  
    public static int tickets = 100;  //static不能省  
    public static String str = new String("哈哈");  //static不能省  
    private Object obj = new Object();       
    public void run()  
    {  
        while (true)  
        {  
            synchronized (obj)  
            {  
                if (tickets > 0)  
                {  
                    System.out.printf("%s线程正在卖出第%d张票\n",  
                        Thread.currentThread().getName(), tickets);  
                    --tickets;    
                }  
                else  
                {  
                    break;  
                }  
            }  
        }  
    }  
} 

 

 

public class rain  
{  
    public static void main(String[] args)  
    {  
        MyThread4 aa1 = new MyThread4();  
        aa1.start();      
              
        MyThread4 aa2 = new MyThread4();  
        aa2.start();          
    }  
} 

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转载自blog.csdn.net/qq_43296599/article/details/87877856
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