leetcode-mid-dynamic programming- Longest Increasing Subsequence-NO

不会。。。

参考:

思路类似于coin那个题,for循环中在满足条件时就及时更新当下位置的信息

def lengthOfLIS(nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if nums==[]:
            return 0
        N = len(nums)
        Dp = [1]*N
        print(N,Dp)
        for i in range(N-1):
            for j in range(0,i+1):
                if nums[i+1]>nums[j]:
                    Dp[i+1] = max(Dp[i+1],Dp[j]+1)
        return max(Dp)

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转载自www.cnblogs.com/rosyYY/p/10981394.html