关于Parameter index out of range (1 > number of parameters, which is 0).

关于Parameter index out of range (1 > number of parameters, which is 0).

解决方法:

stmt = conn.prepareStatement("SELECT * from me.tb_sign  where 1=1");

stmt.setObject(1, "参数1");

这个使用prepareStatement预处理sql时就报这种错,因为:http://www.yayihouse.com/yayishuwu/chapter/1969

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转载自blog.csdn.net/qq_30908729/article/details/91868473