java list map 排序

List<Map<String,Object>> rows = new  Array<Map<String,Object>>();
Map<String,Object> map = new  HashMap<String,Object>();
map.put("yjl",182.1);
rows.add(map)
Map<String,Object> map2 = new  HashMap<String,Object>();
map2.put("yjl",map2);
     //第一种 double 类型排序
    System.out.println("排序前"+rows);
	Collections.sort(rows, new Comparator<Map<Object, Object>>() {
           public int compare(Map<Object, Object> o1,
                              Map<Object, Object> o2) {
               Double d1=Double.parseDouble(o1.get("yjl").toString());
               Double d2=Double.parseDouble(o2.get("yjl").toString());
               return d2.compareTo(d1);
           }
       });
     System.out.println("排序后"+rows);
      //第二种 Integer类型排序
  	Collections.sort(rows, new Comparator<Map<Object, Object>>() {     
             public int compare(Map<Object, Object> o1, Map<Object, Object> o2) {
                  int map2value = Integer.parseInt(o1.get("yjl").toString());
                  int map1value = Integer.parseInt(o2.get("yjl").toString());
                  *//**
                   * 只有在value的值是int是用下面写法
                   * 如果value是其他类型的用compareTo比较
                   *//*
                  return map1value - map2value;
                  //return String.valueOf(map1value).compareTo(String.valueOf(map2value));
              }
       });
       

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转载自blog.csdn.net/weixin_43239106/article/details/92068720