1087. The Time to Take Stones

原文链接: http://www.cnblogs.com/liulangye/archive/2012/10/18/2729148.html

http://acm.timus.ru/problem.aspx?space=1&num=1087

简单博弈 + dp(记忆化搜索)

代码:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<vector>
#include<queue>
#include<map>
#include<stack>
#include<algorithm>
#include<cmath>

using namespace std;
//#pragma comment(linker,"/STACK:1000000000,1000000000")

#define LL long long

const int INF=0x3f3f3f3f;
const int N=10005;
const int M=55;
int win[N];
int choose[M];
int n,m;
int dp(int x)
{
    if(win[x]!=-1)
    return win[x];
    if(x==0)
    {
        win[x]=1;
        return win[x];
    }
    for(int i=0;i<m;++i)
    {
        if(x-choose[i]>=0&&dp(x-choose[i])==2)
        {win[x]=1;break;}
    }
    if(win[x]==-1)
    win[x]=2;
    return win[x];
}
int main()
{
    //freopen("data.txt","r",stdin);
    while(scanf("%d %d",&n,&m)!=EOF)
    {
        for(int i=0;i<m;++i)
        cin>>choose[i];
        memset(win,-1,sizeof(win));
        cout<<dp(n);
    }
    return 0;
}

转载于:https://www.cnblogs.com/liulangye/archive/2012/10/18/2729148.html

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