class GroupDefectsByAssigneeWithContinuationAndOrdering { static void Main()//查询表达式持续通过分组和查询 查询延续 { var query = from defect in SampleData.AllDefects where defect.AssignedTo != null //defect 有41个缺陷 就不一一贴出来了 //{ 1: MP3 files crash system (2013/5/1-2013/5/23, Showstopper/Accepted, Tim Trotter -> Darren Dahlia)} group defect by defect.AssignedTo into grouped select new { Assignee = grouped.Key, Count = grouped.Count() } into result orderby result.Count descending //{ Assignee = {User: Darren Dahlia (Developer)}, Count = 14 } //{ Assignee = {User: Deborah Denton (Developer)}, Count = 9 } //{ Assignee = {User: Tara Tutu (Tester)}, Count = 5 } //{ Assignee = {User: Tim Trotter (Tester)}, Count = 5 } //{ Assignee = {User: Colin Carton (Customer)}, Count = 2 } select result; //{System.Linq.OrderedEnumerable<<>f__AnonymousTypea<Chapter11.Model.User,int>,int>} foreach (var entry in query) { Console.WriteLine("{0}: {1}", entry.Assignee.Name, entry.Count); } } }
多个延续如何使用。目前结果没有拍下,看谁分配到的缺陷最多。
最后的select子句什么都没做,编译器忽略了它。所有查询表达式必须以select或group...by
子句来结尾,所以在查询表达式中必须包含它。而且,你可以自由地针对延续查询使用不同的
投影或执行其他操作---连接、进一步分组等等。
输出
Darren Dahlia: 14
Deborah Denton: 9
Tara Tutu: 5
Tim Trotter: 5
Colin Carton: 2