【codeforces div3 19/10/23】A.Yet Another Dividing into Teams - 代码天地

【codeforces div3 19/10/23】A.Yet Another Dividing into Teams

其他 2019-10-23 13:34:11 阅读次数: 0

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转载自www.cnblogs.com/thjkhdf12/p/11725667.html

【codeforces div3 19/10/23】A.Yet Another Dividing into Teams

【CodeForces 1249A --- Yet Another Dividing into Teams】

A. Yet Another Dividing into Teams

Codeforces Round #595 (Div. 3), problem: (A) Yet Another Dividing into Teams 【math + 贪心排序 +要么1 要么2】

CF598 div3 E. Yet Another Division Into Teams(贪心+DP）

Codeforces Round #598 (Div. 3) E. Yet Another Division Into Teams dp

Codeforces Round #598 (Div. 3)- E. Yet Another Division Into Teams - 动态规划

Codeforces Round #598 (Div. 3) E - Yet Another Division Into Teams （划分数-贪心-模拟）

E. Yet Another Division Into Teams（Codeforces Round #598 (Div. 3)）（划分数-贪心-模拟）

CodeForces Round #527 (Div3) B. Teams Forming

codeforce div3 C Yet Another Walking Robot

E. Yet Another Division Into Teams dp

【CodeForces】Codeforces Round #677 (Div. 3) B. Yet Another Bookshelf （模拟&思维）

Educational Codeforces Round 88 (Rated for Div. 2) D. Yet Another Yet Another Task

Educational Codeforces Round 88 (Rated for Div. 2) D.Yet Another Yet Another Task

CF1256E Yet Another Division Into Teams（动态规划）

codeForces #575 div3

Codeforces - Yet Another Segments Subset

F. Yet another 2D Walking--Codeforces Round #515 (Div. 3)【dp】

Codeforces Round #540 (Div. 3) E. Yet Another Ball Problem(思维)

Codeforces Round #540 (Div. 3) E. Yet Another Ball Problem 构造

Codeforces Round #605 (Div. 3) C. Yet Another Broken Keyboard

// dp +位处理相关 bitmask F - Yet Another Substring Reverse Codeforces Round #590 (Div. 3)

Codeforces Round #617 (Div. 3), problem: (C) Yet Another Walking Robot【map记录坐标点】

Codeforces Round #617 (Div. 3) C Yet Another Walking Robot (map)

Codeforces Round #617 (Div. 3)：C. Yet Another Walking Robot

Codeforces Round #617 (Div. 3) C.Yet Another Walking Robot

Codeforces Round #627 (Div. 3)B. Yet Another Palindrome Problem

Codeforces Round #590 (Div. 3) F - Yet Another Substring Reverse(状压dp)

Codeforces Round #627 (Div. 3) B. Yet Another Palindrome Problem

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