[转]JS获取URL传参方法

原文链接: https://www.mk2048.com/blog/blog.php?id=h02j2ihj12jb&title=%5B%E8%BD%AC%5DJS%E8%8E%B7%E5%8F%96URL%E4%BC%A0%E5%8F%82%E6%96%B9%E6%B3%95
1 function GetQueryString(name) {
2    var reg = new RegExp("(^|&)"   name   "=([^&]*)(&|$)","i");
3    var r = window.location.search.substr(1).match(reg);
4    if (r!=null) return (r[2]); return null;
5 }
6 alert(GetQueryString("参数名1"));
7 alert(GetQueryString("参数名2"));
8 alert(GetQueryString("参数名3"));

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转载自blog.csdn.net/mabeizui9231/article/details/102759550