给一个数字20190318,打印2019年10月18日
month_day = [31,28 ,31, 30, 31, 30 ,31 ,31, 30, 31, 30, 31]
def riqi(date):
# 数据质量,闰年的问题
print(date[0:4]+"年"+date[4:6]+"月"+date[6:8]+"日")
month = int(date[4:6])
day = int(date[6:8])
a = 1
days = 0
while a<month:
days = days+ month_day[a-1]
a=a+1
return "这是今年的第%d天"%(days+day)
s = '20191018'
print(riqi(s))