Python程序员表白

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本文链接： https://blog.csdn.net/Yellow_python/article/details/88415433

print

static

[print('\033[91m'+i,end='',flush=True)for i in('\n'.join(''.join(('I love U '[(x-y)%9]if((x*.05)**2+(y*.1)**2-1)**3-(x*.05)**2*(y*.1)**3<=0else' ')for x in range(-30,30))for y in range(15,-15,-1)))]

dynamic

from time import sleep
[(sleep(1e-5),print('\033[91m'+i,end='',flush=True))for i in('\n'.join(' '.join((u'我爱你'[(x-y)%3]if((x*.05)**2+(y*.1)**2-1)**3-(x*.05)**2*(y*.1)**3<=0 else'  ')for x in range(-30,30,2))for y in range(15,-15,-1)))]

matplotlib

import numpy as np, matplotlib.pyplot as mp
x = np.linspace(-8, 8, 1024)
y1 = .618 * np.abs(x) - .8 * np.sqrt(64 - x ** 2)
y2 = .618 * np.abs(x) + .8 * np.sqrt(64 - x ** 2)
mp.plot(x, y1, color='r')
mp.plot(x, y2, color='r')
mp.show()

绘制二元函数

from sympy import var, plot_implicit
var('x y')
plot_implicit((x**2+y**2-1)**3-x**2*y**3)
plot_implicit(x**2+(y-x**(2/3))**2-1)

$(x^2+y^2-1)^3-x^2y^3=0$

$x^2 + (y - \sqrt[3]{x^2})^2 = 1$