hql语句中like查询 对于 / ' " % 的处理 【转】

public List searchByParas(String authId, String resourceId, Integer state,  
           Integer value, String description) {  
       log.debug("finding KiiUaResAuth instance by example");  
       try {  
           description = description.replace("//", "//////").replace("%", "//%").replace("'", "''");  
           StringBuffer hql = new StringBuffer(  
                   "from KiiUaResAuth as k join k.id.resource as r where k.description like '%"  
                           + description + "%'");  
           if (authId != "") {  
               hql.append(" and k.id.authId='" + authId + "'");  
           }  
           if (resourceId != "") {  
               hql.append(" and r.resourceId='" + resourceId + "'");  
           }  
           if (state != null) {  
               hql.append(" and k.resAuthState=" + state);  
           }  
           if (value != null) {  
               hql.append(" and k.value=" + value);  
           }  
           if (description.indexOf("//") >= 0) {  
               hql.append(" escape '/'");  
           }  
           List results = getHibernateTemplate().find(hql.toString());  
           log.debug("find by example successful, result size: "  
                   + results.size());  
           List toresult = new ArrayList();  
           Object[] objlist = null;  
           if (results.size() != 0) {  
               for (int i = 0; i < results.size(); i++) {  
                   Object objs = results.get(i);  
                   objlist = (Object[]) objs;  
                   if (objlist[0] != null) {  
                       toresult.add((KiiUaResAuth) objlist[0]);  
                   }  
               }  
           }  
           return toresult;  
       } catch (RuntimeException re) {  
           log.error("find by example failed", re);  
           throw new SystemException("UA1202");  
       }  
   }